CBSE 10 - Maths worksheet 1 question 1
Asked by bhawnabansal47809 | 01 Jun, 2022, 07:23: PM x/2 + 2y/3 = - 1 and x – y/3 = 3 By elimination method x/2 + 2y/3 = -1 ... (i) x – y/3 = 3 ... (ii) Multiplying equation (i) by 2, we get x + 4y/3 = - 2 ... (iii) x – y/3 = 3 ... (ii) Subtracting equation (ii) from equation (iii), we get 5y/3 = -5 Dividing by 5 and multiplying by 3, we get y = -15/5 y = - 3 Putting this value in equation (ii), we get x – y/3 = 3 ... (ii) x – (-3)/3 = 3 x + 1 = 3 x = 2 Hence our answer is x = 2 and y = −3. By substitution method x – y/3 = 3 ... (ii) Add y/3 both side, we get x = 3 + y/3 ... (iv) Putting this value in equation (i) we get x/2 + 2y/3 = - 1 ... (i) (3+ y/3)/2 + 2y/3 = -1 3/2 + y/6 + 2y/3 = - 1 Multiplying by 6, we get 9 + y + 4y = - 6 5y = -15 y = - 3 Hence our answer is x = 2 and y = −3. |