What is the molality of kbr in a solution prepared by dissolving 2.21 g or kbr in 897 g or water

Get the answer to your homework problem.

Try Numerade free for 7 days

We don’t have your requested question, but here is a suggested video that might help.

What is the molar concentration of a solution of 36.6 g of KBr (M.M. = 119.0 g/mol) dissolved in enough water to form 750.0 ml of solution?

In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation.

jullianadomeniquemag jullianadomeniquemag

Answer:

Molality is defined as the number of moles of solute in 1 kg of solvent.

In this case the solvent is water, therefore we need to find the number of moles of KBr in 1 kg of water.

Number of moles of KBr - 2.10 g / 119 g/mol = 0.0176 mol

mass of water - 897 g

number of moles of KBr in 897 g - 0.0176 mol

Therefore number of KBr moles in 1000 g - 0.0176 mol / 897 g x 1000 g = 0.0196 mol/kg

therefore molality of KBr is 0.0196 mol/kg

Explanation:

I Hope It Helps

#CarryOnLearning