No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses Open in App Suggest Corrections 0 The ratio in which the x-axis divides the line segment joining the points (6, 4) and (1, −7) is 4 : 7 Explanation; Hint: A line divides internally in the ratio m : n the point P  P = `(("m" + 6"n")/("m" + "n"), (-7"m" + 4"n")/("m" + "n"))` (a, 0) = `(("m" + 6"n")/("m" + "n"), (-7"m" + 4"n")/("m" + "n"))` 0 = `(-7"m" + 4"n")/("m" + "n")` −7m + 4n = 0 4n = 7m `"m"/"n" = 4/7` The ratio is 4 : 7 Concept: The Mid-point of a Line Segment (Mid-point Formula) Is there an error in this question or solution? |
What is the ratio in which the x-axis divides the line segment joining the points 6 4 and 1 7?
Pos Terkait
Copyright © 2024 menakung Inc.
