 Text Solution Answer : A::C Solution : Heat liberated by 10g water `(at 40^@C)` when it converts into water at `0^@C`. <br> `Q = m_1sDeltatheta` <br> `=10xx1xx40` <br> =400cal <br> Mass of ice melted by this heat, <br> `m_2 = Q/L = 400/80 = 5g lt 15g` <br> Therefore, whole ice is not melted. <br> Temperature of mixture is `0^@C`. <br> Mass of water `=m_1 + m_2 = 15g` <br> Mass of ice = 15-`m_2` = 10g. No worries! We‘ve got your back. Try BYJU‘S free classes today!
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What is the result of mixing 20g of water at 80 C to 40g of ice at 10 C?
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