Open in App Suggest Corrections 14 Answer Hint: Transition from n = 4 to n =2 means the electrons jumped from higher energy level orbit to lower energy level orbit by losing energy. There is a relationship between wavenumber and number of orbits where the electron is present. As per Balmer formula \[\overset{-}{\mathop{\text{V}}}\,={{R}_{H}}\left[ \dfrac{1}{n_{1}^{2}}-\dfrac{1}{n_{2}^{2}} \right]\] Where ${{R}_{H}}$ = Rydberg constant${{n}_{1}}$ = lowest energy level orbital in the atom${{n}_{2}}$ = highest energy level orbital in the atom. Complete step by step answer: - So, the electrons release 486 nm of light when it jumps from higher energy level to lower energy level in the atom. Note: If an electron present in an atom absorbs energy then it jumps from lowest energy level to highest energy level and when an electron jumps from higher to lower energy level then it loses energy in the form of light called emission of energy.
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