A ball is thrown up into the air. what happens to the acceleration as the ball rises in the air

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erlycabacolina erlycabacolina

Answer:

Step-by-step explanation:

because its increase the acceleration

thank you for your answer

A ball is thrown vertically upward with an initial speed of v0. It experiences a force of air resistance. The positive direction for all vector quantities is upward. Does the magnitude of the acceleration of the ball increase, decrease, or remain the same as the ball moves upwards?

The Attempt at a Solution

The magnitude of the ball’s acceleration with air resistance increases as the ball moves upwards because air resistance acts downwards, and the acceleration due to gravity also acts downwards. Acceleration becomes more negative, increasing the magnitude of the acceleration. For example, if the acceleration due to gravity is -9.80m/s2 and the acceleration due to air resistance is -1.00m/s2, then: Acceleration without air resistance = -9.80m/s2 Acceleration with air resistance = -9.80m/s2 + (-1.00m/s2) = -10.8m/s2 Comparing only the magnitudes of the accelerations: Magnitude of acceleration without air resistance = 9.80m/s2 Magnitude of acceleration with air resistance = 10.8m/s2 The magnitude of the acceleration with air resistance is greater than the magnitude of the acceleration without air resistance.

However, the AP exam (question 1a) has the same question and this is their answer:

Question: http://apcentral.collegeboard.com/apc/public/repository/_ap05_frq_physics_c_m_45648.pdf
Solution: http://apcentral.collegeboard.com/apc/public/repository/_ap05_sg_physics_c_me_46691.pdf Since velocity is upward, air resistance is downward, in the same direction as gravity. The velocity will decrease, causing the force of air resistance to decrease. Therefore, the net force and thus the total acceleration both decrease.

Which answer is right? Did the AP solution maybe forget that the question asked for magnitude?

Mister T

Magnitude of acceleration without air resistance = 9.80m/s2 Magnitude of acceleration with air resistance = 10.8m/s2
The magnitude of the acceleration with air resistance is greater than the magnitude of the acceleration without air resistance.

As mfb points out, that is not the comparison they're asking you to make. As the ball continues its upward movement, will the magnitude of the acceleration stay at 10.8 m/s², will it decrease, or will it increase?

(I don't see poor phrasing, though).

Likes Badgeray

A ball sitting in a person's hand is at rest. The ball is thrown into the air. There must be some upward acceleration which is greater than the acceleration due to gravity, since in order for the ball to move, the upward force must be greater than the force of gravity. Since the mass of the ball doesn't change, the acceleration upwards must be greater than the acceleration downwards for the upward force to be greater than the downward force.

The instant the ball leaves the hand, what is its acceleration?

a. Acceleration of gravity, downward
b. Upward acceleration from the throw
c. Something else

If a, how it can be that the acceleration changes instantaneously to that of gravity, what happens to the acceleration from the throw?

If b, at some point the only acceleration on the ball must be from gravity (because otherwise the ball would keep going forever like a rocket), yet this means the acceleration is decreasing and at some point it will be 0. Then there is no force acting on the ball and it is moving at a constant velocity, but this doesn't make sense because the ball is certainly accelerating due to gravity.

If c, then what is really happening?

EDIT: It seems that according to the answer of another question here, "a" is correct. However, that question and its answer does not address what happens to the upward acceleration from the hand. Does it instantaneously become zero, such that the ball only has an initial velocity upward but not an initial acceleration upward?

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