The angle of elevation of the top of a tower from a point on the ground, which is 30m away from the

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Question 4 The angle of elevation of the top of a tower from a point on the ground which is 30 m away from the foot of the tower is 30∘. Find the height of the tower.

Solution

Let AB be the height of the tower and C is the point elevation which is 30 m away from the foot of the tower. As per question,

In right $\Delta$ABC,
tan ${30}^{\circ }=\frac{AB}{BC}$
$\Rightarrow \frac{1}{\sqrt{3}}=\frac{AB}{30}$
$\Rightarrow AB=10\sqrt{3}$
Thus, the height of the tower is $10\sqrt{3}$ m.

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Last updated at Dec. 8, 2016 by Teachoo

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