The LCM of two co-prime numbers is 119 find their HCF

Did you notice that 119 = 7 x 17 , that is, its only factors are prime numbers. If we needed the HCF of 7 and 17 it would be 1 If we needed the LCM of 7 and 17 it would be 119 The product of 1 and 119 is 119 Our two numbers are 7 and 17 Further investigation: suppose we have two numbers that have a common factor, e.g. 15 and 24 15 = 3x5 24 = 3x2x2x2 so LCF = 3 HCM = 3x5x8 = 120 product of 3 and 120 = 360 360 = 3x3x5x8 = 3^2 (5x8) which splits into 3x5 and 3x8 notice we have the square of the common factor times the other non-common factors so our 119 = 1^2 (7x17) which splits into 1x7 and 1x17 consider a product such as 5^2 (9x7) or 1575 as the product of the HCF and LCM What were the two numbers? According to the above, they would have been 5x9 and 5x7 or 45 and 35 check for 45 and 35 , the HCF is 5 and the LCM = 5x9x7 or 315 then the product of the LCF and the HCM is 5x315 = 1575

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do you notice that 119=into 17, that os its only factors are prime numbers.If we needed the HCF of 7 and 17 it would be 1.If we need the LCM of 7 and 17 it would be 119.The product of 1 and 119 is 119 is 119.our two numbers are 7 and 17.

the product of hcf and lcm is 119 find the two numbers if none of them is one

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