> Solution Let one of the number be x then other number is (18 − x). Then according to question, 1x+118-x=14⇒18-x+xx(18-x)=14⇒18×4=18x-x2⇒72=18x-x2⇒x2-18x+72=0⇒x2-12x-6x+72=0⇒x(x-12)-6(x-12)=0⇒(x-6)(x-12)=0⇒x-6=0 or x-12=0⇒x=6 or x=12 Since, x being a number, Therefore, When x=12 then another number will be 18-x=18-12=6 And when x=6 then another number will be 18-x=18-6=12 Thus, the two numbers are 6 and 12. Mathematics RD Sharma (2016) Standard X Suggest Corrections |