What is the de Broglie wavelength of electron accelerated through a potential difference of 100V?

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Text Solution

Solution : de Broglie wavelength, `lambda =( ( h )/(p)) =( h )/( sqrt(2mqV))` <br> `= (6.63 xx 10^(-34) )/( sqrt(2 xx 9.1 xx 10^(-31) xx 1.6 xx 10^(-19) xx 100))` <br> `= 1.227 xx 10^(-10) m = 1.227 Å` <br> This wavelength belongs to X -ray spectrum.