Dear Student, Solubility is taken as the amount of solute that can be dissolved in 100 g of solvent. Thus 100 g of water dissolves 40g KCl therefore, 50 g of water will dissolve (40/100) × 50 = 20g of KCl Now, 20g of KCl is required to form a saturated solution in 50g of water. When a saturated solution of potassium chloride is cooled, the solubility potassium chloride in water decreased. As a result the amount of potassium chloride which exceeds its solubility at lower temperature separates out as crystals.Regards
Dear Student, Solubility is taken as the amount of solute that can be dissolved in 100g of solvent. Thus 100g of water dissolves 40g KCl therefore, 50 g of water will dissolve (40/100) × 50 = 20g of KCl Now, 20g of KCl is required to form a saturated solution in 50g of water.
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Hey! The solution is as follows : Solubility of potassium nitrate at 313K = 62/100 100 g of water contains potassium nitrate = 62 g 50 g of water contains potassium nitrate = 62/100 X 50 = 31g Thus, 31 g potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 g of water at 313 K. Hope it helped to clear your delimma Thank you
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150M+ Students 30,000+ Colleges 500+ Exams 1500+ E-books  Text Solution Solution : (a) Mass of potassium chloride in 100 g of water in saturated solution = 46 g <br> Mass of potassium chloride in 50 g of water in saturated solution = `((46 g))/((100 g)) xx (50g) = 23 g` <br> (b) When the solution is cooled, the solubility of salt in water will decrease. This means that upon cooling, it will start separating from the solution in crystalline form. |
What mass of KCl would be needed to form a saturated solution in 50g of water at 313K given the solubility of KCl is 40 at this temperature *?
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