Open in App Suggest Corrections Let the digits at units and tens place of the given number be x and y respectively. Thus, the number is `10y+x.`. The number is 4 more than 6 times the sum of the two digits. Thus, we have ` 10 y + x = 6 (x+y)+4` ` ⇒ 10y +x =6x + 6y + 4` `⇒ 6x + 6y -10y -x=-4 ` ` ⇒ 5x -5y =-4` After interchanging the digits, the number becomes `10x + y.`. If 18 is subtracted from the number, the digits are reversed. Thus, we have ` ( 10y + x )- 18 =10x + y` `⇒ 10x + y -10y -x = -18 ` ` ⇒ 9x -9y =-18` ` ⇒ x -y =-18/9` ` ⇒ x - y = -2` So, we have the systems of equations ` 5x - 4y = -4 ` ` x - y =-2` Here x and y are unknowns. We have to solve the above systems of equations for xand y. Multiplying the second equation by 5 and then subtracting from the first, we have `(5x-4y)-(5x-5y)=-4-(-2xx5)` ` ⇒ 5 x -4y -5x +5y =-4+10` ` ⇒ y = 6` Substituting the value of y in the second equation, we have ` x - 6=-2` `⇒ x = 6-2 ` ` ⇒ x =4`
Hence, the number is `10 xx6+4=64.` Page 2Let the digits at units and tens place of the given number be x and y respectively. Thus, the number is `10 y + x`. The number is 4 times the sum of the two digits. Thus, we have ` 10 y +x =4( x + y)` ` ⇒ 10y + x = 4x + 4y` `⇒ 4x + 4y -10y -x =0 ` ` ⇒ 3x -6y =0` `⇒ 3(x - 2y)=0` ` ⇒ x- 2y =0` ` ⇒ x = 2y` After interchanging the digits, the number becomes `10x + y`. The number is twice the product of the digits. Thus, we have `10y+x=2xy` So, we have the systems of equations ` x = 2y,` ` 10y +x =2xy` Here x and y are unknowns. We have to solve the above systems of equations for xand y. Substituting `x = 2y` in the second equation, we get ` 10y + 2y = 2xx2yxxy` ` ⇒ 12y = 4y^2` ` ⇒ 4y^2-12y =0` ` ⇒ y ( y -3)=0` ` ⇒ y =0` OR `y = 3` Substituting the value of y in the first equation, we have Hence, the number is `10 xx 3+6= 36.` Note that the first pair of solution does not give a two digit number. University Grants Commission (Minimum Standards and Procedures for Award of Ph.D. Degree) Regulations, 2022 notified. As, per the new regulations, candidates with a 4 years Undergraduate degree with a minimum CGPA of 7.5 can enroll for PhD admissions. The UGC NET Final Result for merged cycles of December 2021 and June 2022 was released on 5th November 2022. Along with the results UGC has also released the UGC NET Cut-Off. With tis, the exam for the merged cycles of Dec 2021 and June 2022 have conclude. The notification for December 2022 is expected to be out soon. The UGC NET CBT exam consists of two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions. By qualifying this exam, candidates will be deemed eligible for JRF and Assistant Professor posts in Universities and Institutes across the country. |