Answer ${V_i}$ = I${X_L}$ that is the voltage across the inductance L and it leads the current I by an angle of 90 degrees. ${V_c}$ = I${X_c}$ that is the voltage across capacitor C and it lags the current I by an angle of 90 degrees.Step 2:The product of voltage and current is defined as P=VI$\cos \phi $ =I${R^2}$ Where, cos$\phi $ is the power factor of the circuit and expressed as: cos$\phi $=$\dfrac{{{V_r}}}{v}$ =$\dfrac{R}{Z}$ =$\dfrac{R}{{\sqrt {{{\left( {{X_c} - {X_l}} \right)}^2} + {R^2}} }}$ Hence this is the power in series by the RLC circuit in the AC source. From the above equation option D is correct. Note:For a series RLC circuit, an impedance triangle can be drawn by dividing each side of the voltage triangle by its current, I. The voltage drop across the resistive element is equal to IR, the voltage across the two reactive elements is IX = I${X_L}$ – I${X_c}$ while the source voltage is equal to IZ. Page 2 |